41m-10m^2+45=0

Solution for 41m-10m^2+45=0 equation:

41m-10m^2+45=0

a = -10; b = 41; c = +45;
Δ = b2-4ac
Δ = 412-4·(-10)·45
Δ = 3481
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3481}=59$
$m_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(41)-59}{2*-10}=\frac{-100}{-20}
=+5
$
$m_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(41)+59}{2*-10}=\frac{18}{-20}
=-9/10
$